4a^2-50a+144=0

Solution for 4a^2-50a+144=0 equation:

4a^2-50a+144=0

a = 4; b = -50; c = +144;
Δ = b2-4ac
Δ = -502-4·4·144
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-14}{2*4}=\frac{36}{8}
=4+1/2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+14}{2*4}=\frac{64}{8}
=8
$